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10 moles of nitrogen and 20 moles of hydrogen are made to react to form ammonia. If only $40 %$ of nitrogen reacts, the composition of final mixture is

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4 mol $N_{2}$ , 2 mol $H_{2}$ , 12 mol $N H_{3}$

6 mol $N_{2}$ , 12 mol $H_{2}$ , 8 mol $N H_{3}$

6 mol $N_{2}$ ,8 mol $H_{2}$ , 8 mol $N H_{3}$

4 mole $N_{2}$ , 8 mol $H_{2}$ , 8 mol $N H_{3}$

answer is D.

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Detailed Solution

Balanced equation: $N_{2} + 3 H_{2} \to 2 N H_{3}$
$N_{2}$ $H_{2}$ $N H_{3}$
Taken 10 mol 20 mol 0 mol
Reacted/formed 4 mol 12 mol 8 mol
End of reaction 6 mol 8 mol 8 mol

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