10 moles of ${KMnO}_{4}$ were consumed in each separate titration with oxalic acid, one in presence of $H_{2} {SO}_{4}$ and other in presence of HCl. Identify the correct option.

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25 moles of oxalic acid will be consumed in both cases

No oxalic acid will be consumed in case of HCl and less than 25 moles will be consumed in case of $H_{2} {SO}_{4}$

25 moles of oxalic acid will be consumed with $H_{2} {SO}_{4}$ and less than 25 moles of oxalic acid will be consumed with HCl.

25 moles of oxalic acid will be consumed with $H_{2} {SO}_{4}$ and with HCl more than 25 moles of oxalic acid will be consumed.

answer is D.

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Detailed Solution

25 moles of oxalic acid will be consumed with $H_{2} {SO}_{4}$ and less than 25 moles of oxalic acid will be consumed with HCl.

It can be proved with the following calculations;

$5 \times 10 = 2 \times n_{H_{2}} C_{2} O_{4}$

$n_{H_{2} c_{2} O_{4}} = 25$ [in presence of $H_{2} {SO}_{4} .$ ]

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