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Q.

10 resistors, each of resistance R are connected in series to a battery of emf E and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased n times. The value of n is :

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a

100

b

1

c

1000

d

10

answer is C.

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Detailed Solution

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Initial current =E10R
final current =ER10=10ER
 Ratio =n=10E/RE/10R=100⇒n=100

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10 resistors, each of resistance R are connected in series to a battery of emf E and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased n times. The value of n is :