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10 years ago A was half of B in age. At present the ratio of their ages is 3 : 4. Find the difference of their ages after 3 years

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2 years

1 year

5 years

3 years

answer is C.

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Detailed Solution

$\frac{x + 10}{2 x + 10} = \frac{3}{4}$

$4 x + 40 = 6 x + 30$

$2 x = 10$

$x = 5$

A’s age $\Rightarrow x = 5$

B’s age $\Rightarrow 2 x \Rightarrow 2 \times 5 = 10$

After 3 years

A’s age $= 5 + 3 = 8$

B’s age $= 10 + 3 = 13$

Difference of their ages $= 13 - 8 = 5 y e a r s$

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