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Q.

10 years ago, the average age of a family consisting of 4 members was 24 years. Two children having been born (with age difference of 2 years), the present average age of the family is the same. What is the present age of the youngest child?

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a

5 years 

b

3 years

c

2 years 

d

1 year 

answer is C.

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Detailed Solution

Given that 10 years ago, the average age of a family consisting of 4 members was 24 years

Suppose that the ages of two new children is x,x+2

Given that 

  424+10+x+x+26=242x+2+40=224x+1+20=24x=3

Therefore, the age of youngest child is 3

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