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100 balls each of mass $m$ moving with speed $v$ simultaneously strike a wall normally and reflected back with same speed, in time $t$ s. The total force exerted by the balls on the wall is

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$\frac{m v}{100 t}$

$\frac{100 m v}{t}$

$\frac{200 m v}{t}$

$200 m v t$

answer is D.

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Detailed Solution

The total force exerted can be calculated by

$F = \frac{ΔP}{Δt}$

where P is momentum and t is time.

Therefore, total change in momentum

$ΔP = 100 \times (mv - m (- v)) = 200 mv$

$∴ F = \frac{ΔP}{Δt} = \frac{200 mv}{t}$

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