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Q.

100 g of water at 30°Cis heated. On heating its temperature rises to 40°C. The amount of heat energy supplied to the water is (specific heat of water is 1calg−1 °c−1)           

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a

8000 cal

b

5400 cal

c

80 cal

d

1000 cal

answer is A.

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Detailed Solution

Mass m=100g

Change in temperature  Δt=40−30=10°C

Sw=1cal g−1°C−1

Q=ms  Δ t=100×1×10

Q=1000cal

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