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100 g of water is heated from $30^{0} C$ to $50^{0} C$ ignoring the slight expansion of the water, the change in its internal energy is (Specific heat of water is 4184 J/kg/K)

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84 kJ

8.4 kJ

4.2 kJ

2.1 kJ

answer is B.

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Detailed Solution

$Δ Q = m s Δ T$

$m = 100 g, s = 4184 J / K g . k$

$Δ T = 20^{0} C$ ,

$Δ Q = Δ U + Δ W$

$Δ U = 8.4 k J$

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