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100 J of heat is produce each second in a $2 Ω$ resistor. The potential difference across the resistor will be

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25 V

$10 \sqrt{2} V$

30 V

20 V

answer is D.

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Detailed Solution

$Q = 100 J R = 2 Ω \begin{array}{l} t = 1 s \\ Q = \frac{V^{2}}{R} \times t \\ 100 = \frac{V^{2}}{2} \times (1) \\ V^{2} = 200 \\ V = 10 \sqrt{2} V \end{array}$

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