100 ml mixture of CO and ${CO}_{2}$ is mixed with 30 mL of $O_{2}$ and sparked in eudiometer tube. The residual gas after treatment with aq. KOH has a volume of 10 mL which remains unchanged when treated with alkaline pyrogallol. If all the volumes are under the same conditions, point out the correct options{s).

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The volume of CO that reacts is 60 mL.

The volume of CO that remains unreacted is 10mL.

The volume of $O_{2}$ that remains unreacted is 10mL.

The volume of ${CO}_{2}$ that gets absorbed by aqueous KOH is 90 mL

answer is A, B, D.

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Detailed Solution

The reaction takes place as,

$\begin{array}{l} CO + \frac{1}{2} O_{2} \to {CO}_{2} \\ \begin{array}{ccc} V & 30 & 100 - V \\ V - 60 & - & 60 + 100 - V \\ V - 60 = 10 \\ \Rightarrow & V = 70 ml \end{array} \\ V_{{CO}_{2}} = 30 ml \\ V_{{CO}_{2}} absorbed = 160 - 70 \\ = 90 ml \end{array}$