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100 ml of 0.1 M $H_{2} S O_{4}$ is added to 200 ml of 0.1 M $N a O H$ . What is the $P^{H}$ of resulting mixture?

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Detailed Solution

$H^{+} i o n s = 100 \times 0.1 \times 2 = 20$

$O H^{-} i o n s = 200 \times 0.1 = 20$

$∴ P^{H} = 7$

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