Q.

100 ml of 0.1 M HCl and 100 ml of 0.1 M HOCN are mixed. What is the concentration of "OCN"; and pH of the solution? (Ka=1.2×106) 

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a

2.4×106,2.6

b

1.2×106,1

c

2.6×108,1.6

d

1.2×106,1.3

answer is A.

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Detailed Solution

HCl  H+ + Cl-1 0.1 M × 100 = M × 200  M = 0.05M after dilution

HOCN  H+ + OCN-1 0.1M × 100 = 1M × 200  M= 0.05 after dilurion

Ka = [H+][OCN][HOCN] 1.2 × 10-6 = 0.05 × 0.05 α0.05

[OCN-1] = 0.05 α = 1.2 × 10-6

[H+] = [H+]HCl = 0.05

pH = 1.3

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