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100 ml of 1M HCl, 200 ml of 2M HCl and 300 ml of 3M HCl are mixed with enough water to get 1M solution. The volume of water to be added is (in ml)

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a
600
b
700
c
800
d
125

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detailed solution

Correct option is C

 The quantities provided in the question are:

M1=1M, V1=100 ml

M2=2M, V2=200 ml

M3=3M, V3=300 ml

The product of total mass and volume can be expressed as:

MtotalVtotal=M1V1+M2V2+M3V3

1×Vtotal=1×100+2×200+3×300

Vtotal=1400 ml

Volume of water to be added =Vtotal-(V1+V2+V3)

=1400-(100+200+300)=800 ml

Hence, the required answer is C) 800.

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