100 ml of 1M HCl, 200 ml of 2M HCl and 300 ml of 3M HCl are mixed with enough water to get 1M solution. The volume of water to be added is (in ml)

Factorise: &nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mn>49</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>28</mn><mi>x</mi><mi>y</mi><mo>+</mo><mn>4</mn><msup><mi>y</mi><mn>2</mn></msup></math>

calculate using algebraic identities: 26<math xmlns="http://www.w3.org/1998/Math/MathML"><mo>×</mo></math>34 = __________&nbsp;

Solve:&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>0.86</mn><mo>×</mo><mn>0.86</mn><mo>×</mo><mn>0.86</mn><mo>+</mo><mn>0.14</mn><mo>×</mo><mn>0.14</mn><mo>×</mo><mn>0.14</mn></mrow><mrow><mn>0.86</mn><mo>×</mo><mn>0.86</mn><mo>−</mo><mn>0.86</mn><mo>×</mo><mn>0.14</mn><mo>+</mo><mn>0.14</mn><mo>×</mo><mn>0.14</mn></mrow></mfrac><mo>=</mo></math>

The value of <math><mrow><msup><mrow><mrow><mo>(</mo><mrow><mn>103</mn></mrow><mo>)</mo></mrow></mrow><mn>3</mn></msup><mo>+</mo><msup><mrow><mrow><mo>(</mo><mrow><mn>97</mn></mrow><mo>)</mo></mrow></mrow><mn>3</mn></msup></mrow></math><xml> </xml> is

100 ml of 1M HCl, 200 ml of 2M HCl and 300 ml of 3M HCl are mixed with enough water to get 1M solution. The volume of water to be added is (in ml)

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