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Q.

100 ml of 2M HCl solution completely neutralises 10 g. of a metal carbonate. Then the equivalent weight of the metal is

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a

100

b

12

c

50

d

20

answer is B.

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Detailed Solution

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Given, Given, MHCl=2M  NHCl=2×basicity=2×1=2N

For given neutralization reaction, no. of equivalents of HCl = no. of equivalents of metal carbonate

NV(ml)1000HCl=Wt.Emetal carbonate ; where E=Equivalent weight 100×21000=10Emetal+ECO3-2 0.2=10x+30  ECO3-2=Molar mass2=602 0.2x+6=10 x=20

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100 ml of 2M HCl solution completely neutralises 10 g. of a metal carbonate. Then the equivalent weight of the metal is