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Q.

100 mL of a gas is stored over mercury in mercury manometer at 270C radius of inside column is r and that of outside is R and initially mercury level is equal in both column.

a) If R = r. Find the new temperature (in K) if due to change in temperature outside level of mercury is raised by 20 mm

Patm=1atm

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(i) Assume volume of gas remain constant by some experimental means T1

(ii) Volume does not remain constant πr2=10cm2

T2

(b) If R = 2r and inside level falls by 80 mm 

T3

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Give the answers by adding T1,T2,T3 to the nearest integer

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answer is 1298.

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Detailed Solution

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 (i) P1T1=P1T1T1=780760×300=307.89K

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 (ii)P1V1T1=P2V2T2T2=800760×300100×120=378.94K

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