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Q.

100 ml of an aqueous solution contains 6.023×1021 solute molecules. The solution is diluted to 1 lit. The number of solute molecules present in 10ml of the dilute solution is

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a

6.0×1017

b

6.0×1018

c

6.0×1020

d

6.0×1019

answer is B.

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Detailed Solution

No of molecules in 100 mL of solution =6.023×1021

Diluted to 1000 mL no of molecules of solute does not change so

1000 mL of solution=6.023×1021molecules

10 mL of solution=?

=10×6.023×10211000

=6.023×1019

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