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100 ml of ethyl alcohol [d = 0.92 g/ml] and 900 ml of water [d = 1 g/ml] are mixed to form 1 lit solution. The Molarity and molality of the resulting solution are

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2M and 2m

2M and 2.22m

2.2M and 1.1 m

2M and 1m

answer is B.

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Detailed Solution

C₂H₅OH (solute) H₂O(solvent)

V_s= 100ml V_o =900ml

d_s= 0.92g/cc d_o = 1g/cc

W_s = 100(0.92) =92g ; w₀ = 900(1)=900

GMW=46 g GMW = 18g

$large Molarity =n_sXfrac{1000}{V(inml)}$

$large =frac{92}{46}Xfrac{1000}{1000}=2M$

$large molality=n_sXfrac{1000}{W_o}$

$large =frac{92}{46}Xfrac{1000}{900}=2.22m$

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