100 ml of $O_3,O_2$ mixture was passed through turpentine oil and reduction of 18 ml took place in volume. If 100 ml of this mixture is heated then what will be increase in volume in ml?

Turpentine absorbs  $O_3$
Now, volume of  $O_2=100-18=82ml$
Volume of  $O_3=18ml$
   $2O_3\to 3O_2$
   $O_3\to 3/2O_2$
  1 ml =3/2 ml
  20 ml = 27 ml
Total volume of $O_2=82+27=109ml,$ Hence increase = 109-100=9ml