1000 grams of 1 molal aqueous solution of sucrose (C12H22O11) is prepared by mixing of

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1000 grams of 1 molal aqueous solution of sucrose $(C_{12} H_{22} O_{11})$ is prepared by mixing of

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1000 grams of water and 342 grams of sucrose

820 grams of water and 342 grams of sucrose

About 745 grams of water and 255 grams of sucrose

658 grams of water and 342 grams of sucrose

answer is C.

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Detailed Solution

1000+342=1342g – 342 g
1000g - ?
$∴ \frac{1000 \times 342}{1342} ≃ 255 g . s o l u t e ∴ 745 g . o f H_{2} O$

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