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Q.

1000 N force is required to lift a hook and 10000N force is requires to lift a load slowly. Find power required to lift hook with load with speed $v = 0.5 m s^{- 1}$ .

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a

5.5 kW

b

4.5 kW

c

5 kW

d

1.5 kW

answer is B.

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Detailed Solution

$P = F . V = (1000 + 10000) 0.5 = \frac{11000}{2} = 5500 = 5.5 kw$

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