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Q.

$100 g$ of water is heated from $30^{0} C$ to $50^{0} C$ . Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is $4184 J / k g / K$ )

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a

$2.1 k J$

b

$4.2 k J$

c

$84 k J$

d

$8.4 k J$

answer is A.

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Detailed Solution

$Δ U = Δ Q = m c Δ T = 100 \times 10^{- 3} \times 4184 (50 - 30) \approx 8.4 k J$

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