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100ml $H_{2} O_{2}$ is completely oxidized by 50ml. of 0.1N $K M n O_{4}$ solution in acidic medium. The strength of hydrogen peroxide is

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$3.4 % (\frac{W}{V})$

1.5 $\frac{g}{L}$

$\frac{N}{20}$

$\frac{M}{40}$

answer is A, B.

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Detailed Solution

$\begin{array}{l} N_{1} V_{1} = N_{2} V_{2} \\ N_{1} x100=0.1x50 \\ N_{1} = \frac{5}{100} = 0.05 \\ {strength of H}_{2} O_{2} = \frac{N}{20} o r \frac{M}{40} \\ =0.17 \frac{g}{L} \\ =1.7% (\frac{W}{V}) \end{array}$

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