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Q.

100ml of 2.5 M Sulphuric acid  is diluted to 0.125 N solution. Volume of water added is ------ mL

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a

1950

b

3900

c

4000

d

3600

answer is D.

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Detailed Solution

         V1N1=V2N2   1002.52=V20.125 ;              V2=4000 ml ;        Vwater =V2-V1= 3900 ml ;

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