100ml of KMnO₄ solution is exactly reduced by 100ml of 0.5M oxalic acid under acidic condition. The molarity of KMnO₄ solution is

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0.1M

0.5M

0.2M

0.05M

answer is B.

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Detailed Solution

n-factor for KMnO₄/H⁺ (n₁) = 5 (MnO₄^- → Mn⁺²)

n-factor for H₂C₂O₄ (n₂) = 2 (C₂O₄^-2 → 2CO₂)

$\large \begin{array}{*{20}{c}} {\underline {KMn{O_4}} }&{\underline {{H_2}{C_2}{O_4}} } \\ {{V_1} = 100ml}&{{V_2} = 100ml} \\ {{M_1} = ?}&{{M_2} = {\text{0}}{\text{.5M}}} \\ {{n_1} = 5}&{{n_2} = {\text{2}}} \end{array}\$

KMnO₄ = H₂C₂O₄

V₁N₁ = V₂N₂

100(M₁)5 = 100(0.5)2

M₁ = 0.2

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