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Q.

100ml of water at 200C and 100ml of water at 400C are mixed in calorimeter until constant temperature reached. Now temperature of the mixture is 28C  0. Water equivalent of the calorimeter is

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a

 209 J

b

104.5 J

c

50 J

d

-24.2 J

answer is D.

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Detailed Solution

100ml of water at 20C and 100ml of water at 400C are mixed in calorimeter temperature of the mixture is 280C.

Now,

Heat loss = Heat gained

 100×(40-28)×1=100×(28-20)×1+ water equivalent ×8  1200=800+ water equivalent ×8   water equivalent ×8=1200-800   water equivalent =4008   water equivalent =50 cal=210J

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