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Q.

1014 fissions per second are taking place in a nuclear reactor having efficiency 40%. The energy released per fission is 250 MeV.  The power output of the reactor is

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a

400 W 

b

800 W 

c

200 W 

d

1600 W 

answer is D.

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Detailed Solution

P=40100(Nt)E
P=40100×1014×250×106×1.6×10−19
=1600W

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