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Q.

1021 molecules are removed from 200 mg of CO2. The moles of CO2 left is

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a

2.88 x 10-3

b

28.8 x 10-3

c

288 x 10-3

d

28.8 x 103

answer is A.

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Detailed Solution

1021 molecules =1021 molecule 6.022×1023 molecule /mol=1.66x103 mol 200 mg of CO2=200×103g44g/mol=4.54×103mol.
The number of moles of CO2 remaining = (4.54 -1.66) x 10-3 = 2.88 x 10-3.

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