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$10^{5} g m$ of a sample of water contain $16.2 g m$ of $C a {(H C O_{3})}_{2}$ , it’s hardness is

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100 ppm

200 ppm

300 ppm

60 ppm

answer is D.

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Detailed Solution

$10^{5}$ gm water contain 16.2 gm $C a {(H C O_{3})}_{2}$

$10^{6}$ gm water contain ?

$= \frac{10^{6} \times 16.2}{10^{5}} = 162 g m C a {(H C O_{3})}_{2}$

1 mole $C a {(H C O_{3})}_{2} \equiv$ 1 mole $C a C O_{3}$

162 gm $C a {(H C O_{3})}_{2} \Rightarrow 100 p p m$

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