108g solution of  $AgN{O}_3$ is electrolysed using pt electrodes by passing a charge of 0.1F. The mass of resultant solution left is:

 $$\begin{gathered} A{g}^{+}+e^{-}\stackrel{ }{\to }Ag \\ 2O{H}^{-}\stackrel{ }{\to }{H}_{2}O+\frac{1}{2}{O}_2+2e \end{gathered}$$ 
$\therefore$ Equivalents of $A{g}^{+}$ lost =0.1= Equivalents of $O_2$ formed and escaped.
$\therefore$ Total mass loss $=0.1\times 108+\frac{0.1\times 32}{4}=10.8+0.8=11.6$
$\therefore$ Mass of resulting solution left $=108-11.6=96.4g$