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Q.

10g of calcium carbonate contains

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a

10 moles of CaCO3

b

0.1 g of Calcium

c

1 gram atom of Calcium

d

6×1022atom of Calcium

answer is C.

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Detailed Solution

Molecular mass of CaCO3 is 100 g/mol

So , 100 g of CaCO3 contain =1 mole

For 10 g of CaCO3 contains = 0.1 mole = 0.1 X NA number of CaCO3.

                                                                    = 0.1 X NA number of Ca atoms 

                                                                     = 0.1 X 6.023 X 1023. atoms 

                                                                    =  6.023 X 1022. atoms

 

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