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Q.

10g of calcium carbonate contains

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a

10 moles of ${CaCO}_{3}$

b

0.1 g of Calcium

c

1 gram atom of Calcium

d

$6 \times 10^{22}$ atom of Calcium

answer is C.

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Detailed Solution

Molecular mass of CaCO₃ is 100 g/mol

So , 100 g of CaCO₃ contain =1 mole

For 10 g of CaCO₃ contains = 0.1 mole = 0.1 X N_A number of CaCO₃.

= 0.1 X N_A number of Ca atoms

= 0.1 X 6.023 X 10²³. atoms

= 6.023 X 10²². atoms

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