10ml of a gaseous hydrocarbon on combustion gives 40ml of CO2 and 50ml of H2O vapour under the same conditions. The hydrocarbon is

CxHy+x+y4O2 →xCO2 +y2H2O10ml 10(X +y/4) 10x 10y/2Given 10 x =40x =410y2=50 y=10 Hydrocarbon is C4H10

10ml of a gaseous hydrocarbon on combustion gives 40ml of CO2 and 50ml of H2O vapour under the same conditions. The hydrocarbon is

CxHy+x+y4O2 →xCO2 +y2H2O10ml 10(X +y/4) 10x 10y/2Given 10 x =40x =410y2=50 y=10 Hydrocarbon is C4H10

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10ml of a gaseous hydrocarbon on combustion gives 40ml of CO₂ and 50ml of H₂O vapour under the same conditions. The hydrocarbon is

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C₄H₆

C₆H₁₀

C₄H₈

C₄H₁₀

answer is D.

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$C_{x} H_{y} + (x + \frac{y}{4}) O_{2} \to {xCO}_{2} + \frac{y}{2} H_{2} O$

10ml 10(X +y/4) 10x 10y/2

Given 10 x =40

x =4

$\frac{10 y}{2} = 50 y = 10$

$large therefore$ Hydrocarbon is C₄H₁₀

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10ml of a gaseous hydrocarbon on combustion gives 40ml of CO2 and 50ml of H2O vapour under the same conditions. The hydrocarbon is

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10ml of a gaseous hydrocarbon on combustion gives 40ml of CO₂ and 50ml of H₂O vapour under the same conditions. The hydrocarbon is