10ml of a solution of H2O2 labeled 10 volume strength just decolourise 100ml of potassium permanganate solution acidified with dilute H2 SO4 calculate the amount of potassium permanganate in the given solution.

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10ml of a solution of $H_{2} O_{2}$ labeled 10 volume strength just decolourise 100ml of potassium permanganate solution acidified with dilute $H_{2} S O_{4}$ calculate the amount of potassium permanganate in the given solution.

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0.1563g

0.563g

5.63g

0.256g

answer is B.

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Detailed Solution

$2 H_{2} O_{2} \to 2 H_{2} O + O_{2}$
$22400 m L o f O_{2} \to 68 g H_{2} O_{2}$
$10 m L o f O_{2} \to ?$
$W H_{2} O_{2} = \frac{68 \times 10}{22400} g$
1ml of $H_{2} O_{2}$ contain $\frac{0.0303}{34} m o l = 0.00178$ equivalent weight 10ml of $H_{2} O_{2}$
Therefore 0.0178 equivalent will be present in 100ml of kmno4 solution
Amount of kmno4 in given simple $= \frac{158}{5} \times 0.0178 = 0.563 g$