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10ml of a solution of NaOH found to be completely neutralised by 8mL of a given solution of HCl. If we take 20mL of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralise it will be

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16 mL

12 mL16 mL

8 mL

4 mL

answer is D.

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Detailed Solution

10ml NaOH completely neutralized, 8ml of HCl, 20 ml NaOH completely neutralized by ?

$10 m l - 8 m l$

$20 m l - (x)$

$\Rightarrow x = \frac{25 \times 8}{10} = 16 m l$

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