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10ml of CO is mixed with 25ml air having 20% $O_{2}$ by volume. What would be the final volumes and the gases present, if none of CO and $O_{2}$
is left after the reaction?

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$10 {mlCO}_{2}$

$20 m l N_{2}$

$5 ml C O_{2}$

$24 m l N_{2}$

answer is A.

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Detailed Solution

$\begin{array}{lc} 2 CO + O_{2} & \to 2 {CO}_{2} \end{array} oxygen is 20 % of 25 ml air = 25 \times \frac{20}{100} = 5 ml i n i t i a l : 10 m l 5 m l 0 r e a c t e d : 10 m l 5 m l 10 m l f i n a l : 0 0 10 m l$

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