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Q.

1.1 mole of A are mixed with 2.2 mole of B and the mixture is then kept in one litre flask till the equilibrium is attained A+2B⇌2C+D. At the equilibrium
0.2 mole of C are formed. The equilibrium constant of the reaction is:

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a

0.004

b

0.001

c

0.002

d

0.003

answer is A.

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Detailed Solution

Aa(a-x)+2Bb(b-2x)⇌2C02x+D0x
Given, 2x = 0.2, Also, a = 1.1
x=0.1,b=2.2
∴Kc=(2x)2⋅x(a−x)(b−2x)=(2×0.1)2×0.1(1.1−0.1)(2.2−0.2)2=0.001

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