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1.11 gm of ${CaCI}_{2}$ is added to water forming $500 mI$ solution. $20 ml$ of this solution is taken and diluted 10 folds. Find moles of ${CI}^{-}$ ions in $2$ mI of diluted

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$8 \times 10^{- 6}$

$4 \times 10^{- 6}$

$12 \times 10^{- 8}$

$5 \times 10^{- 6}$

answer is A.

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Detailed Solution

$M = n V$

where n is the number of moles and V is the volume in litres.

$[\frac{1.11}{111}] \times (\frac{20}{1000}) \times \frac{1}{(200)} \times 1000 \times 2 \times \frac{2}{1000} = 8 \times 10^{- 6}$

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