$(1.1{)}^{10000} \mathrm{is} \mathrm{\_\_\_\_\_} 1000.$

$\text{ Given, }(1.1{)}^{10000}=(1+0.1{)}^{10000}$

$$\begin{gathered} ={ }^{10000}{C}_0{+}^{10000}{C}_1\times \left(0.1\right){+}^{10000}{C}_2\times (0.1{)}^2+\text{ other +ve terms } \\ \begin{array}{r}=1+10000\times \left(0.1\right)+\text{ other +ve terms }\\ =1+1000+\text{ other +ve terms }\\ >1000\\ \text{ So, }(1.1{)}^{10000}\text{ is greater than }1000.\end{array} \end{gathered}$$