1.19 gm mixture of Cu and Zn contains AI copper by weight and 3×1021 atom of zine. Find gram atoms of aluminium in given mixture? (At. mass of Al=27;Cu=63.55;Zn=65.0 ) NA=6×1023

Weight of Cu in mixture =1.19×50100=0.595gWZn=3×10216×1023×65=0.595gSo, WAl=1.19−(0.595+0.325)g=0.27gGram atom or mole of Al=0.2727=0.01

1.19 gm mixture of Cu and Zn contains AI copper by weight and 3×1021 atom of zine. Find gram atoms of aluminium in given mixture? (At. mass of Al=27;Cu=63.55;Zn=65.0 ) NA=6×1023

Weight of Cu in mixture =1.19×50100=0.595gWZn=3×10216×1023×65=0.595gSo, WAl=1.19−(0.595+0.325)g=0.27gGram atom or mole of Al=0.2727=0.01

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$1.19 gm$ mixture of Cu and Zn contains AI copper by weight and $3 \times 10^{21}$ atom of zine. Find gram atoms of aluminium in given mixture?
$(At. mass of Al = 27; Cu = 63.55; Zn = 65.0)$
$[N_{A} = 6 \times 10^{23}]$

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Weight of Cu in mixture $= 1.19 \times \frac{50}{100} = 0.595 g$

$W_{Zn} = \frac{3 \times 10^{21}}{6 \times 10^{23}} \times 65 = 0.595 g$

So, $W_{A l} = 1.19 - (0.595 + 0.325) g = 0.27 g$

Gram atom or mole of $Al = \frac{0.27}{27} = 0.01$

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1.19 gm mixture of Cu and Zn contains AI copper by weight and 3×1021 atom of zine. Find gram atoms of aluminium in given mixture? (At. mass of Al=27;Cu=63.55;Zn=65.0 ) NA=6×1023

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$1.19 gm$ mixture of Cu and Zn contains AI copper by weight and $3 \times 10^{21}$ atom of zine. Find gram atoms of aluminium in given mixture?
$(At. mass of Al = 27; Cu = 63.55; Zn = 65.0)$
$[N_{A} = 6 \times 10^{23}]$