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$1 + \frac{1}{\cos^{2} 63 °} - \sec^{2} 27 ° + \frac{1}{\sin^{2} 63 °} - {cosec}^{2} 27 ° =$

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Detailed Solution

1 + \frac{1}{\cos^{2} 63 °} - \sec^{2} 27 ° + \frac{1}{\sin^{2} 63 °} - {cosec}^{2} 27 °

$= 1 + \sec^{2} 63 ° - \sec^{2} 27 ° + {cosec}^{2} 63 ° - {cosec}^{2} 27 °$

$= 1 + {cosec}^{2} 27 ° - {cosec}^{2} 63 ° + {cosec}^{2} 63 ° - {cosce}^{2} 27 °$

$= 1 + 0 = 1$

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