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12.5 ml of a solution containg 6 grams of dibasic acid in one litre was found to be neutralized by 10 ml of a decinormal solution of $NaOH$ the molecular mass of the acid is _____

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answer is 150.

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Detailed Solution

$N = \frac{6}{G E W} \times \frac{1}{1}$

$N_{1} V_{1} = N_{2} V_{2}$

$\frac{6}{G E W} \times 12.5 = 10 \times 0.1$

$G E W = \frac{6 \times 125}{10}$

$G M W = \frac{6 \times 125 \times 2}{10}$

$= \frac{1500}{10}$

$G M W = 150 g$

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