12 coins are tossed 4096 times. The number of times that one can get atleast 2 heads is

Given 12 Coins are tossed 4096 times.

No.of Ways to get no head =1

No.of Ways  to get one head =12

No.of Ways to get at least two heads 

    $$\begin{gathered} =\mathrm{total}-no.of ways to get no head-no.of ways to get one head \\ =4096-1-12 \\ =4096-13 \\ =4083 \end{gathered}$$