12 grams of a calcium carbonate sample with non volatile impurities, on complete decomposition left 7.6 grams of residue. What is the percentage of impurities in the sample ?

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16.6 %

33.3 %

32.4 %

12.4 %

answer is A.

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Detailed Solution

Mass of sample = 12 gms

Mass of residue = 7.68 gms (includes impurities)

$∴$ Mass of $C O_{2}$ released = 12-7.6 = 4.4 gms

$44 g m C O_{2} \equiv 100 g m C a C O_{3}$

$∴ 4.4 g m C O_{2} \equiv 10 g m C a C O_{3}$

$∴$ Mass of impurities = 12-10=2 gms.

$∴$ % impurities $= \frac{2}{12} \times 100 = 16.6 %$

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