12 grams of a mixture of sand and calcium carbonate on strong heating produced 7.6 grams of residue. How many grams of sand is present in the mixture?

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answer is 2.

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Detailed Solution

Given, mass of mixture = 12 grams

Mass of residue = 7.6 grams

${C a C O}_{3} ⟶ C a O + {C O}_{2}$

${CO}_{2}$ is evolved on the heating of mixture.

Mass of ${C O}_{2} = 12 - 7.6 = 4.4 g r a m s$

According to the above reaction, 100 grams of ${C a C O}_{3}$ can evolve 44 grams of ${C O}_{2}$

mass of ${C a C O}_{3}$ that can evolve 4.4 grams of ${C O}_{2}$ =10g

Mass of sand = 12 – 10 = 2 grams

Therefore, 2 grams of sand are present in the mixture.

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