120 gram of solution containing 40% by mass of $N a C l$ are mixed with 200 gram of solution containing 15% by mass $N a C l$ . Determine the mass percent of sodium chloride in the final solution:

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24.4 %

78 %

48.8 %

19.68 %

answer is A.

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Detailed Solution

If 100 gram of $N a C l$ solution contain 40 gram of $N a C l$

Then 120 gram of same $N a C l$ solution contain $\frac{120 \times 40}{100} = 48 g r a m o f N a C l$

If 100 gram of $N a C l$ contain 15 gram of $N a C l$

Then 200 gram of $N a C l$ solution contain $\frac{(200 \times 15)}{100} = 30 g r a m o f N a C l$

Therefore total weight of $N a C l$ is 48+30 = 78 gram

Total weight of solution after mixing both solutions is = 120+200 = 320

Therefore mass percentage of $N a C l$ is $(78 / 320) \times 100 = 24.4$

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