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124 u of $P_{4}$ will contain :

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4 atoms of phosphorus

1 molecule of phosphorus

$4 N_{A}$ atoms of phosphorus

$N_{A}$ molecule of phosphorus

answer is B, C.

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Detailed Solution

The atomic mass of P = 31 amu.

Molecular mass of P₄ = 4 × 31 = 124 amu.

Now, 124 g of P₄ contains 1 mole of P₄ = N_A molecules of Phosphorus=4N_A atoms of P(Phosphorus).

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