$12 g of a non-volatile solute dissolved in 108 g of water produces the relative lowering of vapour pressure of 0 .1 . The molecular mass of the solute is$

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answer is C.

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Detailed Solution

$\frac{P^{o} - P_{s}}{P^{o}} = \frac{n}{N} = \frac{w}{m} \times \frac{M}{W} 0 .1 = \frac{12}{m} \times \frac{18}{108} \Rightarrow m = \frac{12 \times 18}{0 .1 \times 108} = 20$

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