12gr of CH₃COOH and 4gr of NaOH are mixed and diluted to 1 litre solution. If P^Ka of CH₃COOH is 4.8, then P^H of the solution is

Following reaction will take place,

Resultant solution contains an weak acid and its conjugate and so it is an acidic buffer such a system will have a ${\mathrm{P}}^{\mathrm{H}}={\mathrm{P}}^{{\mathrm{K}}_{\mathrm{a}}}+\log \frac{\left[\text{ salt }\right]}{\left[\mathrm{acid}\right]}$

$\Rightarrow P^H=4.8+\log \frac{0.1}{0.1}$

${\mathrm{P}}^{\mathrm{H}}=4.8$