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12L of SO₂ gas diffused through a porous membrane in 20 minutes. Under same conditions 36L of X gas diffused in 30 minutes. The molar mass of the gas ‘X’ in g mol^–1 is :

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answer is C.

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Detailed Solution

$\frac{V_{1}}{V_{2}} X \frac{t_{2}}{t_{1}} = \sqrt{\frac{M_{2}}{M_{1}}}$

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