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Q.

13Tan1xx2+1+Tan1x2+1xdx=

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a

2π

b

π

c

4π

d

π2

answer is B.

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Detailed Solution

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13Tan1xx2+1+Tan1x2+1xdx =10Tan1xx2+1+Tan1x2+1x +03Tan1xx2+1+Tan1x2+1xdx =10Tan1xx2+1-π+cot-1xx2+1dx +03Tan1xx2+1+cot1xx2+1dx tan-1x=cot-11xif x>0                =-π+cot-11x, x<0 =-10π2-π+03π2dx =-π2x-10+π2x03 =-π20-(-1)+π23-0 =-π2+3π2=π

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