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$\int_{1}^{3} (x - 1) (x - 2) (x - 3) d x =$

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answer is D.

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Detailed Solution

$I = \int_{1}^{3} (x - 1) (x - 2) (x - 3) dx = \int_{1}^{3} (4 - x - 1) (4 - x - 2) (4 - x - 3) dx = \int_{1}^{3} (3 - x) (2 - x) (1 - x) dx = - I 2 I = 0 I = 0$

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